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Case Study Class 10 Maths Questions and Answers (Download PDF)
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Case Study Class 10 Maths
If you are looking for the CBSE Case Study class 10 Maths in PDF, then you are in the right place. CBSE 10th Class Case Study for the Maths Subject is available here on this website. These Case studies can help the students to solve the different types of questions that are based on the case study or passage.
CBSE Board will be asking case study questions based on Maths subjects in the upcoming board exams. Thus, it becomes an essential resource to study.
The Case Study Class 10 Maths Questions cover a wide range of chapters from the subject. Students willing to score good marks in their board exams can use it to practice questions during the exam preparation. The questions are highly interactive and it allows students to use their thoughts and skills to solve the given Case study questions.
Download Class 10 Maths Case Study Questions and Answers PDF (Passage Based)
Download links of class 10 Maths Case Study questions and answers pdf is given on this website. Students can download them for free of cost because it is going to help them to practice a variety of questions from the exam perspective.
Case Study questions class 10 Maths include all chapters wise questions. A few passages are given in the case study PDF of Maths. Students can download them to read and solve the relevant questions that are given in the passage.
Students are advised to access Case Study questions class 10 Maths CBSE chapter wise PDF and learn how to easily solve questions. For gaining the basic knowledge students can refer to the NCERT Class 10th Textbooks. After gaining the basic information students can easily solve the Case Study class 10 Maths questions.
Case Study Questions Class 10 Maths Chapter 1 Real Numbers
Case Study Questions Class 10 Maths Chapter 2 Polynomials
Case Study Questions Class 10 Maths Chapter 3 Pair of Equations in Two Variables
Case Study Questions Class 10 Maths Chapter 4 Quadratic Equations
Case Study Questions Class 10 Maths Chapter 5 Arithmetic Progressions
Case Study Questions Class 10 Maths Chapter 6 Triangles
Case Study Questions Class 10 Maths Chapter 7 Coordinate Geometry
Case Study Questions Class 10 Maths Chapter 8. Introduction to Trigonometry
Case Study Questions Class 10 Maths Chapter 9 Some Applications of Trigonometry
Case Study Questions Class 10 Maths Chapter 10 Circles
Case Study Questions Class 10 Maths Chapter 12 Areas Related to Circles
Case Study Questions Class 10 Maths Chapter 13 Surface Areas & Volumes
Case Study Questions Class 10 Maths Chapter 14 Statistics
Case Study Questions Class 10 Maths Chapter 15 Probability
How to Solve Case Study Based Questions Class 10 Maths?
In order to solve the Case Study Based Questions Class 10 Maths students are needed to observe or analyse the given information or data. Students willing to solve Case Study Based Questions are required to read the passage carefully and then solve them.
While solving the class 10 Maths Case Study questions, the ideal way is to highlight the key information or given data. Because, later it will ease them to write the final answers.
Case Study class 10 Maths consists of 4 to 5 questions that should be answered in MCQ manner. While answering the MCQs of Case Study, students are required to read the paragraph as they can get some clue in between related to the topics discussed.
Also, before solving the Case study type questions it is ideal to use the CBSE Syllabus to brush up the previous learnings.
Features Of Class 10 Maths Case Study Questions And Answers Pdf
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- Accurate answers of all the Case-based questions given in the PDF.
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- Case study class 10 maths helps in exam preparation since, CBSE Class 10 Question Papers contain case-based questions.
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Class 10 Maths Chapter 3 Case Based Questions - Pair of Linear Equations in Two Variables
Case study - 1.
Refer situation 1 : Q1: If the fixed charges of auto rickshaw be Rs x and the running charges be Rs y km/hr, the pair of linear equations representing the situation is (a) x + 10y =110, x + 15y = 75 (b) x + 10y = 75, x + 15y = 110 (c) 10x + y = 110, 15x + y = 75 (d) 10x + y = 75, 15x + y = 110 Ans: (b) Explanation: The cost of the auto rickshaw ride consists of two components - a fixed charge (x) and a variable charge based on the distance of the journey (y per km). The total cost of the ride would therefore be the sum of these two components. In the first situation, the auto rickshaw ride in city A costs Rs 75 for a 10 km journey and Rs 110 for a 15 km journey. We can express these two situations as two linear equations: For the 10 km journey: x + 10y = 75 (equation 1) For the 15 km journey: x + 15y = 110 (equation 2) Where x is the fixed charge and y is the cost per km. Therefore, the pair of linear equations representing the situation is x + 10y = 75, x + 15y = 110 (option b). Q2: A person travels a distance of 50km. The amount he has to pay is (a) Rs.155 (b) Rs.255 (c) Rs.355 (d) Rs.455 Ans: (c) Explanation: To solve this case-based problem, we first need to understand the relationship between distance traveled and the charge paid. This can be represented as a linear equation in the form of y = mx + c, where y is the charge paid, m is the rate charged per km, x is the distance traveled, and c is the fixed charge. From Situation 1, we have two equations based on the given data: 1) 75 = 10m + c 2) 110 = 15m + c Subtracting equation 1 from equation 2, we get: 35 = 5m So, m = 35/5 = 7. This means the rate charged per km in city A is Rs. 7. Substituting m = 7 in equation 1, we get: 75 = 10*7 + c So, c = 75 - 70 = 5. This means the fixed charge in city A is Rs. 5. So, the total charge for traveling a distance of x km in city A is given by the equation: Charge = 7x + 5 Now, let's calculate the charge for traveling a distance of 50km in city A: Charge = 7*50 + 5 = Rs. 355 Therefore, the answer is (c) Rs. 355. Refer situation 2: Q3: What will a person have to pay for travelling a distance of 30km? (a) Rs.185 (b) Rs.289 (c) Rs.275 (d) Rs.305 Ans: (b) Explanation: To solve this problem, we first need to find the rate of the fare per kilometer and the fixed charge in city B. We can solve this problem by making two equations from the given situations and then solve them simultaneously. Let's take the fixed charge as F (in Rs.) and the rate per kilometer as R (in Rs. per km). From the given situation 2, we know that: For a journey of 8km, the charge paid is Rs 91. For a journey of 14km, the charge paid is Rs 145. So, we can formulate two equations: 1) F + 8R = 91 2) F + 14R = 145 Subtract equation 1 from equation 2 and we get 6R = 54, therefore R = 54/6 = 9 Rs per km. Substitute the value of R in equation 1, we get F = 91 - 8*9 = 91 - 72 = 19 Rs. So, the fixed charge is Rs 19 and the fare per kilometer is Rs 9 in city B. Now, to find out what a person will have to pay for traveling a distance of 30km, we add the fixed charge to the product of the fare per kilometer and the distance. Therefore, the fare for 30km = F + 30R = 19 + 30*9 = 19 + 270 = Rs 289. So, the correct answer is (b) Rs.289.
Case Study - 2
Based on the above information, answer the following questions: Q1: Form the pair of linear equations in two variables from this situation. Ans: Area of two bedrooms= 10x sq.m Area of kitchen = 5y sq.m 10x + 5y = 95 2x + y =19 Also, x + 2+ y = 15 x + y = 13 Q2: Find the length of the outer boundary of the layout. Ans: Length of outer boundary = 12 + 15 + 12 + 15 = 54m Q3: Find the area of each bedroom and kitchen in the layout. Ans: On solving two equation part(i) x = 6m and y = 7m area of bedroom = 5 x 6 = 30m area of kitchen = 5 x 7 = 35m Q4: Find the area of living room in the layout. Ans: Area of living room = (15 x 7) – 30 = 105 – 30 = 75 sq.m Q5: Find the cost of laying tiles in kitchen at the rate of Rs. 50 per sq.m. Ans: Total cost of laying tiles in the kitchen = Rs.50 x 35 = Rs1750.
Case Study - 3
A test consists of ‘True’ or ‘False’ questions. One mark is awarded for every correct answer while ¼ mark is deducted for every wrong answer. A student knew answers to some of the questions. Rest of the questions he attempted by guessing. He answered 120 questions and got 90 marks.
Q2: How many questions did he guess? Ans: Let the no of questions whose answer is known to the student x and questions attempted by cheating be y x + y =120 x – 1/4y =90 solving these two x = 96 and y = 24 He attempted 24 questions by guessing. Q3: If answer to all questions he attempted by guessing were wrong and answered 80 correctly, then how many marks he got? Ans: Let the no of questions whose answer is known to the student x and questions attempted by cheating be y x + y =120 x – 1/4y =90 solving these two x = 96 and y = 24 Marks = 80- ¼ 0f 40 =70
Q4: If answer to all questions he attempted by guessing were wrong, then how many questions answered correctly to score 95 marks? Ans: Let the no of questions whose answer is known to the student x and questions attempted by cheating be y x + y =120 x – 1/4y =90 solving these two x = 96 and y = 24 x – 1/4 of (120 – x) = 95 5x = 500, x = 100
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Case Based Questions: Pair of Linear Equations in Two Variables Free PDF Download
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